android之在 Kotlin 中，将 Long 转换为 uint32 ByteArray 并将 Int 转换为 uint8 的最简洁方法是什么

fun longToByteArray(value: Long): ByteArray { 
    val bytes = ByteArray(8) 
    ByteBuffer.wrap(bytes).putLong(value) 
    return Arrays.copyOfRange(bytes, 4, 8) 
} 
 
fun intToUInt8(value: Int): ByteArray { 
    val bytes = ByteArray(4) 
    ByteBuffer.wrap(bytes).order(ByteOrder.LITTLE_ENDIAN).putInt(value and 0xff) 
    var array = Arrays.copyOfRange(bytes, 0, 1) 
    return array 
} 

请您参考如下方法:

我不喜欢使用 ByteBuffer因为它增加了对 JVM 的依赖。相反，我使用:

fun longToUInt32ByteArray(value: Long): ByteArray { 
    val bytes = ByteArray(4) 
    bytes[3] = (value and 0xFFFF).toByte() 
    bytes[2] = ((value ushr 8) and 0xFFFF).toByte() 
    bytes[1] = ((value ushr 16) and 0xFFFF).toByte() 
    bytes[0] = ((value ushr 24) and 0xFFFF).toByte() 
    return bytes 
}