c++之析构函数中的动态转换

这个代码合法吗？

class Base1 { 
}; 
 
class Base2 { 
public: 
    virtual ~Base2() { 
        if (!dynamic_cast<Base1*>(this)) 
            std::cout << "aaaa" << std::endl; 
    } 
    Base2() { 
    } 
}; 
 
class MyClass: public Base1, public Base2 { 
public: 
    MyClass() { 
    } 
    virtual ~MyClass() { 
        std::cout << "bbb" << std::endl; 
    } 
}; 
 
int main() { 
    MyClass s; 
    return 0; 
} 

请您参考如下方法:

也许我自己找到了解决方案，答案是否定的，这是不可能的:

来自 bullet 6 of cppreference.com documentation :

When dynamic_cast is used in a constructor or a destructor (directly or indirectly), and expression refers to the object that's currently under construction/destruction, the object is considered to be the most derived object. If new-type is not a pointer or reference to the constructor's/destructor's own class or one of its bases, the behavior is undefined.